242=u^2

Solution for 242=u^2 equation:

242=u^2

We move all terms to the left:

242-(u^2)=0

We add all the numbers together, and all the variables

-1u^2+242=0

a = -1; b = 0; c = +242;
Δ = b2-4ac
Δ = 02-4·(-1)·242
Δ = 968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{968}=\sqrt{484*2}=\sqrt{484}*\sqrt{2}=22\sqrt{2}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{2}}{2*-1}=\frac{0-22\sqrt{2}}{-2}
=-\frac{22\sqrt{2}}{-2}
=-\frac{11\sqrt{2}}{-1}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{2}}{2*-1}=\frac{0+22\sqrt{2}}{-2}
=\frac{22\sqrt{2}}{-2}
=\frac{11\sqrt{2}}{-1}
$